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출처: http://www.w3schools.com/PHP/php_ajax_database.asp

AJAX Database Example

The following example will demonstrate how a web page can fetch information from a database with AJAX:

Example


Firstname Lastname Age Hometown Job
Joseph Swanson 39 Quahog Police Officer



Example Explained - The MySQL Database

The database table we use in the example above looks like this:

id FirstName LastName Age Hometown Job
1 Peter Griffin 41 Quahog Brewery
2 Lois Griffin 40 Newport Piano Teacher
3 Joseph Swanson 39 Quahog Police Officer
4 Glenn Quagmire 41 Quahog Pilot


Example Explained - The HTML Page

When a user selects a user in the dropdown list above, a function called "showUser()" is executed. The function is triggered by the "onchange" event:

<html>
<head>
<script type="text/javascript">
function showUser(str)
{
if (str=="")
  {
  document.getElementById("txtHint").innerHTML="";
  return;
  }
if (window.XMLHttpRequest)
  {// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }
else
  {// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=function()
  {
  if (xmlhttp.readyState==4 && xmlhttp.status==200)
    {
    document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
    }
  }
xmlhttp.open("GET","getuser.php?q="+str,true);
xmlhttp.send();
}
</script>
</head>
<body>

<form>
<select name="users" onchange="showUser(this.value)">
<option value="">Select a person:</option>
<option value="1">Peter Griffin</option>
<option value="2">Lois Griffin</option>
<option value="3">Glenn Quagmire</option>
<option value="4">Joseph Swanson</option>
</select>
</form>
<br />
<div id="txtHint"><b>Person info will be listed here.</b></div>

</body>
</html>

The showUser() function does the following:

  • Check if a person is selected
  • Create an XMLHttpRequest object
  • Create the function to be executed when the server response is ready
  • Send the request off to a file on the server
  • Notice that a parameter (q) is added to the URL (with the content of the dropdown list)

The PHP File

The page on the server called by the JavaScript above is a PHP file called "getuser.php".

The source code in "getuser.php" runs a query against a MySQL database, and returns the result in an HTML table:

<?php
$q=$_GET["q"];

$con = mysql_connect('localhost', 'peter', 'abc123');
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("ajax_demo", $con);

$sql="SELECT * FROM user WHERE id = '".$q."'";

$result = mysql_query($sql);

echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>Age</th>
<th>Hometown</th>
<th>Job</th>
</tr>";

while($row = mysql_fetch_array($result))
  {
  echo "<tr>";
  echo "<td>" . $row['FirstName'] . "</td>";
  echo "<td>" . $row['LastName'] . "</td>";
  echo "<td>" . $row['Age'] . "</td>";
  echo "<td>" . $row['Hometown'] . "</td>";
  echo "<td>" . $row['Job'] . "</td>";
  echo "</tr>";
  }
echo "</table>";

mysql_close($con);
?>

Explanation: When the query is sent from the JavaScript to the PHP file, the following happens:

  1. PHP opens a connection to a MySQL server
  2. The correct person is found
  3. An HTML table is created, filled with data, and sent back to the "txtHint" placeholder


question?
출처: http://stackoverflow.com/questions/2593317/ajax-display-mysql-data-with-value-from-multiple-select-boxes

I'm using the W3 Schools example: http://www.w3schools.com/PHP/php_ajax_database.asp to display a table of database data given the choice from a single select box. How can I modify this to include another select box, say for example I wanted records matching a name and an age?

link|edit|flag

33% accept rate


2 Answers

up vote 0 down vote accepted

Change

<select name="users" onchange="showUser()" id="name_select">

ADD age drop down from 1 to 100

<select name="age" onchange="showUser()" id="age_select">
 
<option value="1">1</option>
 
<option value="2">2</option>
                   |
 
<option value="100">100</option>
</select>

Change

function showUser(str)
{
xmlhttp
=GetXmlHttpObject();
if (xmlhttp==null)
 
{
  alert
("Browser does not support HTTP Request");
 
return;
 
}
name
= document.getElementByID('name_select').value
age
= document.getElementByID('age_select').value
var url="getuser.php";
url
=url+"?q="+str+"&age="+age;
url
=url+"&sid="+Math.random();
xmlhttp
.onreadystatechange=stateChanged;
xmlhttp
.open("GET",url,true);
xmlhttp
.send(null);
}

change in php

$age=$_GET["age"];
$sql
="SELECT * FROM user WHERE id = '".$q."' and age=".$age;
link|edit|flag


Won't this be a problem if they don't select an age? – dclowd9901 Apr 7 '10 at 15:00

I'm having problems, now nothing happens if I change the selections – Robert Apr 7 '10 at 15:14

@Robert sorry dear your showUser(str) now should be showUser() – Salil Apr 8 '10 at 3:56

Works great now, thanks! – Robert Apr 8 '10 at 8:39

You can try this (the following piece of code is not tested, but it should work)

The HTML Page

<html>
<head>
<script type="text/javascript" src="selectuser.js"></script>
</head>
<body>

<form>
Select a User:
<select name="users" id="users">
<option value="1">Peter Griffin</option>
<option value="2">Lois Griffin</option>
<option value="3">Glenn Quagmire</option>
<option value="4">Joseph Swanson</option>
</select>

Select an age:
<select name="age" id="age">
<option value="39">39</option>
<option value="40">40</option>
<option value="41">41</option>
<option value="42">42</option>
</select>

<input type='button' value='Refresh Data' onclick="showUser(document.getElementById('users').value,document.getElementById('age').value)">
</form>
<br />
<div id="txtHint"><b>Person info will be listed here.</b></div>

</body>
</html>

The Java script code as:

var xmlhttp;

function showUser(str,age)
{
xmlhttp
=GetXmlHttpObject();
if (xmlhttp==null)
 
{
  alert
("Browser does not support HTTP Request");
 
return;
 
}
var url="getuser.php";
url
=url+"?q="+str+"&a="+age;
url
=url+"&sid="+Math.random();
xmlhttp
.onreadystatechange=stateChanged;
xmlhttp
.open("GET",url,true);
xmlhttp
.send(null);
}

function stateChanged()
{
if (xmlhttp.readyState==4)
{
document
.getElementById("txtHint").innerHTML=xmlhttp.responseText;
}
}

function GetXmlHttpObject()
{
if (window.XMLHttpRequest)
 
{
 
// code for IE7+, Firefox, Chrome, Opera, Safari
 
return new XMLHttpRequest();
 
}
if (window.ActiveXObject)
 
{
 
// code for IE6, IE5
 
return new ActiveXObject("Microsoft.XMLHTTP");
 
}
return null;
}

The PHP Page as

<?php
$q
=$_GET["q"];
$a
=$_GET["a"];

$con
= mysql_connect('localhost', 'peter', 'abc123');
if (!$con)
 
{
 
die('Could not connect: ' . mysql_error());
 
}

mysql_select_db
("ajax_demo", $con);

$sql
="SELECT * FROM user WHERE id = '".$q."' and age='".$a."'";

$result
= mysql_query($sql);

echo
"<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>Age</th>
<th>Hometown</th>
<th>Job</th>
</tr>"
;

while($row = mysql_fetch_array($result))
 
{
  echo
"<tr>";
  echo
"<td>" . $row['FirstName'] . "</td>";
  echo
"<td>" . $row['LastName'] . "</td>";
  echo
"<td>" . $row['Age'] . "</td>";
  echo
"<td>" . $row['Hometown'] . "</td>";
  echo
"<td>" . $row['Job'] . "</td>";
  echo
"</tr>";
 
}
echo
"</table>";

mysql_close
($con);
?>


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